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15n^2-13n-2=0
a = 15; b = -13; c = -2;
Δ = b2-4ac
Δ = -132-4·15·(-2)
Δ = 289
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{289}=17$$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-13)-17}{2*15}=\frac{-4}{30} =-2/15 $$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-13)+17}{2*15}=\frac{30}{30} =1 $
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